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0=x^2+2x-1.732
We move all terms to the left:
0-(x^2+2x-1.732)=0
We add all the numbers together, and all the variables
-(x^2+2x-1.732)=0
We get rid of parentheses
-x^2-2x+1.732=0
We add all the numbers together, and all the variables
-1x^2-2x+1.732=0
a = -1; b = -2; c = +1.732;
Δ = b2-4ac
Δ = -22-4·(-1)·1.732
Δ = 10.928
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-\sqrt{10.928}}{2*-1}=\frac{2-\sqrt{10.928}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+\sqrt{10.928}}{2*-1}=\frac{2+\sqrt{10.928}}{-2} $
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